The perimeter of a rectangle is 50 units, and its length is 14 units. What is the width of the rectangle?
P=2×( length + width )
Given that the perimeter (P) of the rectangle is 50 units and the length is 14 units, we can substitute these values into the formula and solve for the width (W):
50 units=2×(14 units +width)
First, we'll simplify the equation:
50 units=28 units+2×width
50 units−28 units=2×width
22 units=2×width
Now, we'll divide both sides by 2 to isolate the width:
width=22/2 units
width=11 units
Therefore, the width of the rectangle is 11 units.
With a focus on mathematical calculations, Learnerscamp provides dynamic tutorials, real-world applications, and problem-solving scenarios that empower students to grasp mathematical concepts with ease. Our adaptive learning algorithms ensure personalized learning paths, allowing students to progress at their own pace while receiving instant feedback to reinforce their understanding.
Learnerscamp goes the extra mile by incorporating a robust assessment system that enables students to gauge their understanding through comprehensive tests. Our adaptive testing module dynamically tailors assessments to each student's proficiency level, providing a personalized evaluation of their mathematical knowledge.
sample Question screanshot
Upon completing a test, students receive a detailed and insightful report that not only highlights their overall performance but also breaks down their scores on a per-question basis. This granular analysis allows students to identify specific areas that may need improvement fostering a targeted and efficient approach to learning.
sample report screanshot